In the interval [0,ฯ/2], area lying between the curves y = tanx and y = cotx and the X-axis is
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Integration, Area between curves
Set up integral: โซ(tanx - cotx) dx from 0 to ฯ/2
Simplify integrand
Evaluate to get log2 sq. units
Wrong interval consideration
๐ข Uh oh! Incorrect answer, Try again
Consider area between curves
Integration, Area between curves
Set up integral: โซ(tanx - cotx) dx from 0 to ฯ/2
Simplify integrand
Evaluate to get log2 sq. units
Wrong interval consideration
The area of the region bounded by the lines y = x+1, x=3 and x=5 is
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Area under curve formula
Set up integral: โซ(x+1) dx from 3 to 5
Integrate: xยฒ/2 + x
Evaluate at limits to get 10 sq. units
Not considering limits correctly
๐ข Uh oh! Incorrect answer, Try again
Use area under curve formula
Area under curve formula
Set up integral: โซ(x+1) dx from 3 to 5
Integrate: xยฒ/2 + x
Evaluate at limits to get 10 sq. units
Not considering limits correctly
If a curve passes through the point (1,1) and at any point (x,y) on the curve, the product of the slope of its tangent and x co-ordinate of the point is equal to the y co-ordinate of the point, then the curve also passes through the point
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Differential equation solving techniques
Form differential equation: x(dy/dx) = y
Solve: dy/y = dx/x
Get y = cx where c=1 from (1,1)
Wrong initial condition usage
๐ข Uh oh! Incorrect answer, Try again
Recognize separable differential equation
Differential equation solving techniques
Form differential equation: x(dy/dx) = y
Solve: dy/y = dx/x
Get y = cx where c=1 from (1,1)
Wrong initial condition usage
The area of the region bounded by the line y=x and the curve y=xยณ is
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Area between curves formula
Find intersection points: x=0,1
Area = โซโยน(x-xยณ) dx
Evaluate to get 0.5
Wrong integration limits
๐ข Uh oh! Incorrect answer, Try again
Consider region between curves
Area between curves formula
Find intersection points: x=0,1
Area = โซโยน(x-xยณ) dx
Evaluate to get 0.5
Wrong integration limits