An alkali metal hydride reacts with diborane to give a tetrahedral reducing agent 'B'. Identify 'A' and 'B'.
🥳 Wohoo! Correct answer
NaH + B₂H₆ → NaBH₄ in diethyl ether.
Diborane reacts with alkali hydrides in diethyl ether to form NaBH₄.
Reaction mechanism: 2NaH + B₂H₆ → 2NaBH₄.
Final result: 'A' = (C₂H₅)₂O, 'B' = NaBH₄.
Misunderstanding reducing agent formation processes.
😢 Uh oh! Incorrect answer, Try again
Relate diborane reactions to the formation of reducing agents.
NaH + B₂H₆ → NaBH₄ in diethyl ether.
Diborane reacts with alkali hydrides in diethyl ether to form NaBH₄.
Reaction mechanism: 2NaH + B₂H₆ → 2NaBH₄.
Final result: 'A' = (C₂H₅)₂O, 'B' = NaBH₄.
Misunderstanding reducing agent formation processes.
Which compound possesses the "C-H" bond with the lowest bond dissociation energy?
🥳 Wohoo! Correct answer
C-H bond strength ∝ Lack of hyperconjugation.
Bond dissociation energy decreases in the presence of hyperconjugation.
Toluene exhibits hyperconjugation effects, reducing bond strength.
Final result: Toluene has the lowest bond dissociation energy.
Overlooking hyperconjugation effects on bond energy.
😢 Uh oh! Incorrect answer, Try again
Examine hyperconjugation effects on bond dissociation energy.
C-H bond strength ∝ Lack of hyperconjugation.
Bond dissociation energy decreases in the presence of hyperconjugation.
Toluene exhibits hyperconjugation effects, reducing bond strength.
Final result: Toluene has the lowest bond dissociation energy.
Overlooking hyperconjugation effects on bond energy.
Water softening by Clark's process uses...
🥳 Wohoo! Correct answer
Lime reaction forms insoluble carbonates for softening.
Clark's process removes temporary hardness using slaked lime (Ca(OH)₂).
Calcium bicarbonate reacts with lime to form insoluble calcium carbonate.
Final result: Reagent = Ca(OH)₂.
Misidentifying reagents for water softening.
😢 Uh oh! Incorrect answer, Try again
Relate temporary hardness removal to lime addition.
Lime reaction forms insoluble carbonates for softening.
Clark's process removes temporary hardness using slaked lime (Ca(OH)₂).
Calcium bicarbonate reacts with lime to form insoluble calcium carbonate.
Final result: Reagent = Ca(OH)₂.
Misidentifying reagents for water softening.
The distinguishing test between methanoic acid and ethanoic acid is...
🥳 Wohoo! Correct answer
Tollen's test for methanoic acid.
Methanoic acid reacts with Tollen's reagent due to its aldehyde-like structure, while ethanoic acid does not.
Reaction: Methanoic acid → Positive Tollen's test; Ethanoic acid → Negative.
Final result: Tollen's test distinguishes methanoic acid.
Confusing methanoic acid’s behavior with typical carboxylic acids.
😢 Uh oh! Incorrect answer, Try again
Recall tests for aldehyde-like structures in organic acids.
Tollen's test for methanoic acid.
Methanoic acid reacts with Tollen's reagent due to its aldehyde-like structure, while ethanoic acid does not.
Reaction: Methanoic acid → Positive Tollen's test; Ethanoic acid → Negative.
Final result: Tollen's test distinguishes methanoic acid.
Confusing methanoic acid’s behavior with typical carboxylic acids.
The correct statement regarding Lewis acidity of boron halides is...
🥳 Wohoo! Correct answer
pπ-pπ bonding ∝ Orbital overlap efficiency.
Lewis acidity decreases with increasing back bonding strength.
Maximum pπ-pπ back bonding occurs in BF₃ due to small size and high orbital overlap.
Final result: BF₃ has the strongest pπ-pπ bonding.
Confusing pπ-pπ bonding effects on Lewis acid strength.
😢 Uh oh! Incorrect answer, Try again
Relate Lewis acid strength to pπ-pπ bonding in halides.
pπ-pπ bonding ∝ Orbital overlap efficiency.
Lewis acidity decreases with increasing back bonding strength.
Maximum pπ-pπ back bonding occurs in BF₃ due to small size and high orbital overlap.
Final result: BF₃ has the strongest pπ-pπ bonding.
Confusing pπ-pπ bonding effects on Lewis acid strength.
Number of possible alkynes with the formula C₅H₈ is...
🥳 Wohoo! Correct answer
Structures: CH₃-C≡C-CH₂-CH₃, etc.
Use structural formula to determine all possible distinct alkynes for C₅H₈.
Possible structures: CH₃-C≡C-CH₂-CH₃, CH≡C-CH₂-CH₂-CH₃, CH≡C-CH-CH₃-CH₃.
Final result: Total = 3 possible alkynes.
Miscounting possible structural isomers.
😢 Uh oh! Incorrect answer, Try again
Relate molecular formula to structural possibilities for alkynes.
Structures: CH₃-C≡C-CH₂-CH₃, etc.
Use structural formula to determine all possible distinct alkynes for C₅H₈.
Possible structures: CH₃-C≡C-CH₂-CH₃, CH≡C-CH₂-CH₂-CH₃, CH≡C-CH-CH₃-CH₃.
Final result: Total = 3 possible alkynes.
Miscounting possible structural isomers.
The hydrolysis of optically active 2-bromobutane with aqueous NaOH results in...
🥳 Wohoo! Correct answer
SN1 → Racemic mixture.
Hydrolysis of 2-bromobutane undergoes SN1 mechanism, producing a racemic mixture of (+) and (-) enantiomers.
Reaction involves carbocation intermediate, leading to racemic mixture formation.
Final result: Product = (±)-butan-2-ol.
Confusing mechanism with SN2 (non-racemic product).
😢 Uh oh! Incorrect answer, Try again
Recall SN1 mechanism and racemic product formation.
SN1 → Racemic mixture.
Hydrolysis of 2-bromobutane undergoes SN1 mechanism, producing a racemic mixture of (+) and (-) enantiomers.
Reaction involves carbocation intermediate, leading to racemic mixture formation.
Final result: Product = (±)-butan-2-ol.
Confusing mechanism with SN2 (non-racemic product).
H₂O₂ cannot oxidize...
🥳 Wohoo! Correct answer
Oxidizing agent hierarchy: O₃ > H₂O₂ > others.
H₂O₂ is a weaker oxidizing agent compared to O₃.
Confirm inability of H₂O₂ to oxidize O₂ due to stability of O₂.
Final result: H₂O₂ cannot oxidize O₃.
Misinterpreting oxidizing ability of H₂O₂ as stronger than O₃.
😢 Uh oh! Incorrect answer, Try again
Carefully compare oxidizing power of H₂O₂ and O₃.
Oxidizing agent hierarchy: O₃ > H₂O₂ > others.
H₂O₂ is a weaker oxidizing agent compared to O₃.
Confirm inability of H₂O₂ to oxidize O₂ due to stability of O₂.
Final result: H₂O₂ cannot oxidize O₃.
Misinterpreting oxidizing ability of H₂O₂ as stronger than O₃.
Electrophile that participates in nitration of benzene is
🥳 Wohoo! Correct answer
Nitration mechanism
Write nitration mechanism: H₂SO₄ + HNO₃ → NO₂⁺ + HSO₄⁻ + H₂O
Identify electrophile formation
Show attack on benzene ring
Confusing electrophiles
😢 Uh oh! Incorrect answer, Try again
Consider electrophilic species
Nitration mechanism
Write nitration mechanism: H₂SO₄ + HNO₃ → NO₂⁺ + HSO₄⁻ + H₂O
Identify electrophile formation
Show attack on benzene ring
Confusing electrophiles
In the following sequence of reactions: A Reduction→ B HNO₂→ CH₃CH₂OH, The compound A is
🥳 Wohoo! Correct answer
Reduction mechanisms
Work backwards from ethanol product
Identify diazonium intermediate from HNO₂ reaction
Determine original nitrile: CH₃CN
Missing intermediate steps
😢 Uh oh! Incorrect answer, Try again
Consider reduction pathways
Reduction mechanisms
Work backwards from ethanol product
Identify diazonium intermediate from HNO₂ reaction
Determine original nitrile: CH₃CN
Missing intermediate steps
When a brown compound of Mn (A) is treated with HCl, it gives a gas (B). The gas (B) taken in excess reacts with NH₃ to give an explosive compound(C)
🥳 Wohoo! Correct answer
Balanced equations for each step
Identify A as MnO₂: MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
B is Cl₂ gas
C forms as NCl₃: NH₃ + 3Cl₂ → NCl₃ + 3HCl
Missing intermediate steps
😢 Uh oh! Incorrect answer, Try again
Follow stepwise reactions
Balanced equations for each step
Identify A as MnO₂: MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
B is Cl₂ gas
C forms as NCl₃: NH₃ + 3Cl₂ → NCl₃ + 3HCl
Missing intermediate steps
Reactivity of order of halides for dehydrohalogenation is
🥳 Wohoo! Correct answer
Bond energy values
Compare bond strengths: C-F > C-Cl > C-Br > C-I
Analyze leaving group ability
Consider bond dissociation energies
Not considering leaving group ability
😢 Uh oh! Incorrect answer, Try again
Think about bond strength trend
Bond energy values
Compare bond strengths: C-F > C-Cl > C-Br > C-I
Analyze leaving group ability
Consider bond dissociation energies
Not considering leaving group ability
Replacement of Cl⁻ of Chlorobenzene to give phenol requires drastic conditions, but Cl⁻ of 2,4-dinitro chlorobenzene is readily replaced. This is because
🥳 Wohoo! Correct answer
None required
Consider electronic effects
Analyze resonance structures
Understand nucleophilic substitution
Not considering resonance effects
😢 Uh oh! Incorrect answer, Try again
Look at electron withdrawal effects
None required
Consider electronic effects
Analyze resonance structures
Understand nucleophilic substitution
Not considering resonance effects
In the reaction Ethanol PCl₅→ X alc.KOH→ Y H₂SO₄,Room temp.→ Z, the product Z is
🥳 Wohoo! Correct answer
None required
Write reaction sequence
Identify intermediates
Determine final product
Missing intermediate steps
😢 Uh oh! Incorrect answer, Try again
Follow reaction mechanism
None required
Write reaction sequence
Identify intermediates
Determine final product
Missing intermediate steps
Which is true regarding nitrogen?
🥳 Wohoo! Correct answer
N≡N bond formation
Examine N₂ triple bond formation
Analyze p orbital overlap in N₂
Understand strong pπ - pπ bonding due to small size
Confusing with other p-block elements
😢 Uh oh! Incorrect answer, Try again
Consider orbital overlap
N≡N bond formation
Examine N₂ triple bond formation
Analyze p orbital overlap in N₂
Understand strong pπ - pπ bonding due to small size
Confusing with other p-block elements
The property which is not true about Fluorine is
🥳 Wohoo! Correct answer
Bond energy trends
Compare F-F bond strength with other halogens
Analyze electron-electron repulsion in F₂ molecule
Note low F-F bond dissociation energy due to small size
Assuming stronger bonds due to electronegativity
😢 Uh oh! Incorrect answer, Try again
Consider size and electron repulsion
Bond energy trends
Compare F-F bond strength with other halogens
Analyze electron-electron repulsion in F₂ molecule
Note low F-F bond dissociation energy due to small size
Assuming stronger bonds due to electronegativity
Select wrong chemical reaction
🥳 Wohoo! Correct answer
Correct: NaOCl formation
Balance equations
Check products
Find incorrect
Balancing equations
😢 Uh oh! Incorrect answer, Try again
Wrong products
Correct: NaOCl formation
Balance equations
Check products
Find incorrect
Balancing equations
Which reagent cannot be used to oxidize primary alcohols to aldehydes?
🥳 Wohoo! Correct answer
R-CH₂OH → RCHO
Check oxidizing power
Consider conditions
Identify unsuitable
Oxidizing agent strength
😢 Uh oh! Incorrect answer, Try again
Strong oxidant goes to acid
R-CH₂OH → RCHO
Check oxidizing power
Consider conditions
Identify unsuitable
Oxidizing agent strength
In which reaction does homolytic bond fission occur?
🥳 Wohoo! Correct answer
Cl₂ -(light)→ 2Cl·
Consider bond breaking
Check radical formation
Identify mechanism
Mechanism confusion
😢 Uh oh! Incorrect answer, Try again
Look for symmetrical breaking
Cl₂ -(light)→ 2Cl·
Consider bond breaking
Check radical formation
Identify mechanism
Mechanism confusion
Identify correct statement about isomers
🥳 Wohoo! Correct answer
Position isomers
Compare structures
Check isomer type
Verify position
Isomer classification
😢 Uh oh! Incorrect answer, Try again
Same formula different -OH
Position isomers
Compare structures
Check isomer type
Verify position
Isomer classification
Plaster of Paris is represented as
🥳 Wohoo! Correct answer
CaSO₄·½H₂O
Identify hydrate
Check water ratio
Compare with gypsum
Hydrate formula
😢 Uh oh! Incorrect answer, Try again
Partial hydration
CaSO₄·½H₂O
Identify hydrate
Check water ratio
Compare with gypsum
Hydrate formula
3ClO⁻(aq) → ClO⁻ + 2Cl⁻ is an example of
🥳 Wohoo! Correct answer
ClO⁻ → Cl⁻ reduction
Check oxidation states
Track Cl changes
Identify type
Oxidation state errors
😢 Uh oh! Incorrect answer, Try again
Follow e⁻ flow
ClO⁻ → Cl⁻ reduction
Check oxidation states
Track Cl changes
Identify type
Oxidation state errors
Which of the following will be the most stable diazonium salt (RN₂⁺X⁻)?
🥳 Wohoo! Correct answer
Resonance structures of ArN₂⁺
Compare resonance
Check stability
Consider electron delocalization
Students ignore resonance stabilization
😢 Uh oh! Incorrect answer, Try again
Look for aromatic stabilization
Resonance structures of ArN₂⁺
Compare resonance
Check stability
Consider electron delocalization
Students ignore resonance stabilization
Tertiary alkyl halide is practically inert to substitution by SN2 mechanism because of
🥳 Wohoo! Correct answer
R₃C-X + Nu⁻ → No reaction
Consider nucleophile approach
Check steric factors
Evaluate mechanism
Students ignore spatial requirements
😢 Uh oh! Incorrect answer, Try again
Back-side attack blocked
R₃C-X + Nu⁻ → No reaction
Consider nucleophile approach
Check steric factors
Evaluate mechanism
Students ignore spatial requirements
What is the increasing order of acidic strength among: (i) p-methoxy phenol (ii) p-methyl phenol (iii) p-nitro phenol?
🥳 Wohoo! Correct answer
Ph-OH acidity affected by substituents
Compare substituent effects
Consider resonance
Evaluate electron effects
Students ignore electronic effects
😢 Uh oh! Incorrect answer, Try again
#NAME?
Ph-OH acidity affected by substituents
Compare substituent effects
Consider resonance
Evaluate electron effects
Students ignore electronic effects
Which of the following statements is true in the case of alkyl halides?
🥳 Wohoo! Correct answer
C-X dipole moment
Check electronegativity difference
Consider bond polarity
Evaluate intermolecular forces
Students confuse polarity with solubility
😢 Uh oh! Incorrect answer, Try again
Look for C-X bond polarity
C-X dipole moment
Check electronegativity difference
Consider bond polarity
Evaluate intermolecular forces
Students confuse polarity with solubility
When the vapours of tertiary butyl alcohol are passed through heated copper at 573 K, the product formed is
🥳 Wohoo! Correct answer
(CH₃)₃COH → (CH₃)₂C=CH₂ + H₂O
Consider dehydration
Check Saytzeff's rule
Evaluate stability
Students forget stability rules
😢 Uh oh! Incorrect answer, Try again
Most stable alkene forms
(CH₃)₃COH → (CH₃)₂C=CH₂ + H₂O
Consider dehydration
Check Saytzeff's rule
Evaluate stability
Students forget stability rules
Which of the following ions will cause hardness in water?
🥳 Wohoo! Correct answer
Ca²⁺ + CO₃²⁻ → CaCO₃
Consider ion charge
Check solubility
Evaluate precipitation
Students often include all metal ions
😢 Uh oh! Incorrect answer, Try again
Look for divalent cations
Ca²⁺ + CO₃²⁻ → CaCO₃
Consider ion charge
Check solubility
Evaluate precipitation
Students often include all metal ions
During the fusion of organic compound with sodium metal, nitrogen present in the organic compound is converted into
🥳 Wohoo! Correct answer
N + C → CN⁻
Identify N-containing product
Consider redox state
Follow fusion mechanism
Students confuse different sodium salts of nitrogen
😢 Uh oh! Incorrect answer, Try again
Sodium fusion test
N + C → CN⁻
Identify N-containing product
Consider redox state
Follow fusion mechanism
Students confuse different sodium salts of nitrogen
Identify the following compound which exhibits geometrical isomerism
🥳 Wohoo! Correct answer
Isomerism requires restricted rotation
Check double bond position
Consider substituent arrangement
Verify free rotation
Students often forget to check for symmetrical substitution
😢 Uh oh! Incorrect answer, Try again
Look for C=C bond
Isomerism requires restricted rotation
Check double bond position
Consider substituent arrangement
Verify free rotation
Students often forget to check for symmetrical substitution
H₂O₂ is
🥳 Wohoo! Correct answer
H₂O₂ can oxidize and reduce
Check oxidation state of O
Consider possible reactions
Evaluate dual nature
Confusing dual behavior of H₂O₂ in reactions.
😢 Uh oh! Incorrect answer, Try again
-1 oxidation state of O
H₂O₂ can oxidize and reduce
Check oxidation state of O
Consider possible reactions
Evaluate dual nature
Confusing dual behavior of H₂O₂ in reactions.
For the redox reaction xMnO₄⁻ + yH₂C₂O₄ + zH⁺ → mMn²⁺ + nCO₂ + pH₂O
🥳 Wohoo! Correct answer
Oxidation + Reduction half reactions
Balance atoms
Balance charges
Balance H⁺ and O₂
Missing intermediate steps in balancing redox equations.
😢 Uh oh! Incorrect answer, Try again
Follow systematic balancing
Oxidation + Reduction half reactions
Balance atoms
Balance charges
Balance H⁺ and O₂
Missing intermediate steps in balancing redox equations.
Resonance effect is not observed in
🥳 Wohoo! Correct answer
No π-orbital overlap in sp³ carbon
Check conjugation
Verify electron delocalization
Identify broken conjugation
Not identifying conjugation breaks
😢 Uh oh! Incorrect answer, Try again
Look for break in conjugation
No π-orbital overlap in sp³ carbon
Check conjugation
Verify electron delocalization
Identify broken conjugation
Not identifying conjugation breaks
Eutrophication causes
🥳 Wohoo! Correct answer
Nutrients → Algal growth → O₂ depletion
Define eutrophication
Check nutrient levels
Assess water quality
Confusing cause and effect
😢 Uh oh! Incorrect answer, Try again
Excess nutrients lead to algal bloom
Nutrients → Algal growth → O₂ depletion
Define eutrophication
Check nutrient levels
Assess water quality
Confusing cause and effect
Which of the following is NOT true regarding the usage of hydrogen as a fuel?
🥳 Wohoo! Correct answer
H₂ + ½O₂ → H₂O
Compare properties
Check storage conditions
Verify practical limitations
Not considering physical properties of H₂
😢 Uh oh! Incorrect answer, Try again
H₂ has very low liquefaction temperature
H₂ + ½O₂ → H₂O
Compare properties
Check storage conditions
Verify practical limitations
Not considering physical properties of H₂
The number of π-bonds and σ-bonds present in naphthalene are respectively
🥳 Wohoo! Correct answer
C₁₀H₈ structure
Count C-C π bonds (5)
Count total single bonds (C-C and C-H)
Sum up all σ bonds (19)
Confusing aromatic bonds with regular double bonds
😢 Uh oh! Incorrect answer, Try again
Draw naphthalene structure and count bond types
C₁₀H₈ structure
Count C-C π bonds (5)
Count total single bonds (C-C and C-H)
Sum up all σ bonds (19)
Confusing aromatic bonds with regular double bonds
0.1 mole of XeF₆ is treated with 1.8 g of water. The product obtained is
🥳 Wohoo! Correct answer
XeF₆ + H₂O → XeOF₄ + 2HF
Calculate molar ratio of XeF₆:H₂O (1.8g H₂O = 0.1 mole)
XeF₆ + H₂O → XeOF₄ + 2HF based on 1:1 ratio
XeOF₄ is the main product when XeF₆ reacts with controlled amount of water
Students often forget to calculate moles of water and consider stoichiometry
😢 Uh oh! Incorrect answer, Try again
Consider the stoichiometric ratio of reactants
XeF₆ + H₂O → XeOF₄ + 2HF
Calculate molar ratio of XeF₆:H₂O (1.8g H₂O = 0.1 mole)
XeF₆ + H₂O → XeOF₄ + 2HF based on 1:1 ratio
XeOF₄ is the main product when XeF₆ reacts with controlled amount of water
Students often forget to calculate moles of water and consider stoichiometry
If Aniline is treated with 1:1 mixture of con. HNO₃ and con. H₂SO₄, p-nitroaniline and m-nitroaniline are formed nearly in equal amounts. Thus
🥳 Wohoo! Correct answer
C₆H₅NH₂ + H⁺ → C₆H₅NH₃⁺
Consider protonation of amine group
Protonated NH₃⁺ is meta-directing
Equal amounts due to partial protonation
Students often forget about protonation in strongly acidic conditions
😢 Uh oh! Incorrect answer, Try again
Think about effect of strong acid on amine
C₆H₅NH₂ + H⁺ → C₆H₅NH₃⁺
Consider protonation of amine group
Protonated NH₃⁺ is meta-directing
Equal amounts due to partial protonation
Students often forget about protonation in strongly acidic conditions
Which of the following statement is correct?
🥳 Wohoo! Correct answer
2F₂ + 2H₂O → 4HF + O₂
Compare oxidizing strengths of F₂ and Cl₂
F₂ is the strongest oxidizing agent among halogens
Only F₂ can oxidize H₂O to O₂ due to its higher oxidizing power
Students often confuse oxidizing power order of halogens
😢 Uh oh! Incorrect answer, Try again
Remember F₂ has highest electronegativity and oxidizing power among halogens
2F₂ + 2H₂O → 4HF + O₂
Compare oxidizing strengths of F₂ and Cl₂
F₂ is the strongest oxidizing agent among halogens
Only F₂ can oxidize H₂O to O₂ due to its higher oxidizing power
Students often confuse oxidizing power order of halogens
Which of the following is NOT a greenhouse gas?
🥳 Wohoo! Correct answer
None
Check atmospheric role
Compare structures
Identify non-IR active
Greenhouse effect
😢 Uh oh! Incorrect answer, Try again
Greenhouse gases absorb IR
None
Check atmospheric role
Compare structures
Identify non-IR active
Greenhouse effect
Which of the following is NOT a pair of functional isomers?
🥳 Wohoo! Correct answer
None
Check molecular formula
Compare functions
Identify non-isomers
Isomer types
😢 Uh oh! Incorrect answer, Try again
Same molecular formula needed
None
Check molecular formula
Compare functions
Identify non-isomers
Isomer types
The metal that produces H₂ with both dil HCl and NaOH (aq) is
🥳 Wohoo! Correct answer
Zn + 2NaOH → Na₂ZnO₂ + H₂
Check amphoteric nature
Verify reactions
Compare metals
Amphoteric behavior
😢 Uh oh! Incorrect answer, Try again
Amphoteric metal reacts with acid and base
Zn + 2NaOH → Na₂ZnO₂ + H₂
Check amphoteric nature
Verify reactions
Compare metals
Amphoteric behavior
The oxide of potassium that does not exist is
🥳 Wohoo! Correct answer
None
Check oxidation states
Verify stability
Identify non-existent
Oxide types
😢 Uh oh! Incorrect answer, Try again
K forms +1 oxidation state
None
Check oxidation states
Verify stability
Identify non-existent
Oxide types
The oxidation number of nitrogen atoms in NH₄NO₃ are
🥳 Wohoo! Correct answer
None
Check N in NH₄⁺
Check N in NO₃⁻
Assign oxidation states
Oxidation number rules
😢 Uh oh! Incorrect answer, Try again
Sum of oxidation numbers = 0
None
Check N in NH₄⁺
Check N in NO₃⁻
Assign oxidation states
Oxidation number rules
Aqueous solution of a salt (A) forms dense white precipitate with BaCl₂ solution. The precipitate dissolves in dilute HCl to produce a gas (B) which decolourises acidified KMnO₄ solution
🥳 Wohoo! Correct answer
SO₃²⁻ + 2H⁺ → SO₂ + H₂O
Formation of BaSO₃ ppt
Dissolution in HCl
SO₂ reduces KMnO₄
Confusion between sulfite and sulfate
😢 Uh oh! Incorrect answer, Try again
Focus on reducing property of SO₂
SO₃²⁻ + 2H⁺ → SO₂ + H₂O
Formation of BaSO₃ ppt
Dissolution in HCl
SO₂ reduces KMnO₄
Confusion between sulfite and sulfate
How many moles of acidified K₂Cr₂O₇ is required to liberate 6 moles of I₂ from an aqueous solution of I⁻?
🥳 Wohoo! Correct answer
Cr₂O₇²⁻ + 6I⁻ → 2Cr³⁺ + 3I₂
Balance redox equation
Calculate mole ratio
Find required moles
Mole concept
😢 Uh oh! Incorrect answer, Try again
Use balanced equation
Cr₂O₇²⁻ + 6I⁻ → 2Cr³⁺ + 3I₂
Balance redox equation
Calculate mole ratio
Find required moles
Mole concept
Prolonged exposure of chloroform in humans may cause damage to liver. It is due to the formation of the following compound
🥳 Wohoo! Correct answer
CHCl₃ + [O] → COCl₂ + HCl
Oxidation of CHCl₃
Formation of COCl₂
Toxicity mechanism
Oxidation products
😢 Uh oh! Incorrect answer, Try again
Think about oxidation product
CHCl₃ + [O] → COCl₂ + HCl
Oxidation of CHCl₃
Formation of COCl₂
Toxicity mechanism
Oxidation products
Which is not true for oxidation?
🥳 Wohoo! Correct answer
Oxidation = +ve change in oxidation number
Define oxidation
Check electron loss
Check change in oxidation state
Confusing oxidation definition
😢 Uh oh! Incorrect answer, Try again
Remember oxidation definition
Oxidation = +ve change in oxidation number
Define oxidation
Check electron loss
Check change in oxidation state
Confusing oxidation definition
In which of the following compounds, an element exhibits two different oxidation states?
🥳 Wohoo! Correct answer
N in NH₄⁺ = -3; N in NO₃⁻ = +5
Calculate oxidation states
Compare within compound
N has +1 and -3 in NH₄NO₃
Forgetting to check all atoms
😢 Uh oh! Incorrect answer, Try again
Different oxidation states of same element
N in NH₄⁺ = -3; N in NO₃⁻ = +5
Calculate oxidation states
Compare within compound
N has +1 and -3 in NH₄NO₃
Forgetting to check all atoms
Which property of CO₂ makes it biologically and geo-chemically important?
🥳 Wohoo! Correct answer
CO₂ + H₂O ⇌ H₂CO₃ ⇌ H⁺ + HCO₃⁻
Consider CO₂ properties
Understand biological role
CO₂ solubility affects pH balance
Confusing different properties
😢 Uh oh! Incorrect answer, Try again
CO₂ + H₂O ⇌ H₂CO₃ equilibrium
CO₂ + H₂O ⇌ H₂CO₃ ⇌ H⁺ + HCO₃⁻
Consider CO₂ properties
Understand biological role
CO₂ solubility affects pH balance
Confusing different properties
The IUPAC name for CH₃-C(=O)-CH₂-CH₂-C(=O)-OH is
🥳 Wohoo! Correct answer
COOH > C=O
Identify functional groups
Number carbon chain
Name as acid derivative
Confusing numbering rules
😢 Uh oh! Incorrect answer, Try again
Highest priority group is acid
COOH > C=O
Identify functional groups
Number carbon chain
Name as acid derivative
Confusing numbering rules
Identify the products A and B in the reactions: R-X + AgCN → A + AgX; R-X + KCN → B + KX
🥳 Wohoo! Correct answer
R-X + AgCN → RNC; R-X + KCN → RCN
Understand nucleophilic nature
AgCN gives RNC (kinetic)
KCN gives RCN (thermodynamic)
Confusing products with different nucleophiles
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AgCN and KCN give different products
R-X + AgCN → RNC; R-X + KCN → RCN
Understand nucleophilic nature
AgCN gives RNC (kinetic)
KCN gives RCN (thermodynamic)
Confusing products with different nucleophiles
The major product obtained when ethanol is heated with excess of conc. H₂SO₄ at 443K is
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CH₃CH₂OH → CH₂=CH₂ + H₂O
Identify dehydration reaction conditions
Consider temperature and catalyst
Elimination of water forms ethene
Confusing dehydration with dehydrogenation
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Conc. H₂SO₄ acts as dehydrating agent
CH₃CH₂OH → CH₂=CH₂ + H₂O
Identify dehydration reaction conditions
Consider temperature and catalyst
Elimination of water forms ethene
Confusing dehydration with dehydrogenation
An organic compound with molecular formula C₇H₈O dissolves in NaOH and gives characteristic colour with FeCl₃. On treatment with bromine, it gives a tribromo derivative C₇H₅OBr₃. The compound is
🥳 Wohoo! Correct answer
C₇H₈O + 3Br₂ → C₇H₅OBr₃ + 3HBr
Identify phenolic compound
Consider bromination pattern
Meta directing OH group
Confusing substitution patterns
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Trisubstitution occurs at 2,4,6 positions
C₇H₈O + 3Br₂ → C₇H₅OBr₃ + 3HBr
Identify phenolic compound
Consider bromination pattern
Meta directing OH group
Confusing substitution patterns
A transition metal exists in its highest oxidation state. It is expected to behave as
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M^n+ + e⁻ → M^(n-1)+
Consider electron configuration
Highest oxidation state means maximum electrons lost
Can accept electrons = oxidizing agent
Confusing oxidizing and reducing agents
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Highest oxidation state means strong oxidizing nature
M^n+ + e⁻ → M^(n-1)+
Consider electron configuration
Highest oxidation state means maximum electrons lost
Can accept electrons = oxidizing agent
Confusing oxidizing and reducing agents
Oxidation number of S in H₂S₂O₈
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H₂S₂O₈ oxidation state calc
Write structure
Calculate charges
Balance total
Oxidation state rules
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Sum of oxidation states = 0
H₂S₂O₈ oxidation state calc
Write structure
Calculate charges
Balance total
Oxidation state rules
Formation of X, Y and Z in C₆H₅CN -(i)SnCl₂+HCl/(ii)H₃O⁺)→ X -(con.KOH)→ Y + Z
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Stephen reduction followed by Cannizzaro
Identify nitrile reduction
Check aldehyde formation
Analyze base reaction
Mechanism confusion
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Consider disproportionation
Stephen reduction followed by Cannizzaro
Identify nitrile reduction
Check aldehyde formation
Analyze base reaction
Mechanism confusion
Better reagent to oxidize primary alcohols to aldehyde
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RCH₂OH -(PCC)→ RCHO
Compare oxidizing power
Check over-oxidation
Consider selectivity
Oxidation control confusion
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Mild oxidizing agent
RCH₂OH -(PCC)→ RCHO
Compare oxidizing power
Check over-oxidation
Consider selectivity
Oxidation control confusion
Pair of compounds having same boiling point
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Enantiomers
Compare structures
Check stereochemistry
Analyze properties
Stereochemistry confusion
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Physical properties of enantiomers
Enantiomers
Compare structures
Check stereochemistry
Analyze properties
Stereochemistry confusion
Aniline does not undergo
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C₆H₅NH₂ + AlCl₃ → No reaction
Check -NH₂ effect
Analyze Lewis acid reaction
Consider electronic factors
All aromatic reactions possible
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#NAME?
C₆H₅NH₂ + AlCl₃ → No reaction
Check -NH₂ effect
Analyze Lewis acid reaction
Consider electronic factors
All aromatic reactions possible
Identify products A,B,C in CH₃CH₂Br -(KCN/alc)→ A -(LiAlH₄)→ B -(HNO₂/0°C)→ C
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Nucleophilic substitution
Follow reaction sequence
Identify intermediates
Check rearrangement
Product sequence confusion
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SN2 followed by reduction
Nucleophilic substitution
Follow reaction sequence
Identify intermediates
Check rearrangement
Product sequence confusion
In 8MnO₄⁻ + 3S₂O₃²⁻ + H₂O → 8MnO₂ + 6SO₄²⁻ + 2OH⁻, a and y are
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MnO₄⁻ + e⁻ → MnO₂
Balance Mn
Balance S
Balance charge
Difficulty in balancing complex equations
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Check stoichiometry
MnO₄⁻ + e⁻ → MnO₂
Balance Mn
Balance S
Balance charge
Difficulty in balancing complex equations
The reducing agent in given equations: 4Ag⁺ + 8CN⁻ + 2H₂O + O₂ → 4[Ag(CN)₂]⁻ + 4OH⁻ ; 2[Ag(CN)₂]⁻ + Zn → [Zn(CN)₄]²⁻ + 2Ag
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Zn → Zn²⁺ + 2e⁻
Identify oxidation states
Find species oxidized
Compare all options
Confusion between oxidizing/reducing agents
😢 Uh oh! Incorrect answer, Try again
Look for electron loss
Zn → Zn²⁺ + 2e⁻
Identify oxidation states
Find species oxidized
Compare all options
Confusion between oxidizing/reducing agents
NO₂ gas is:
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No formula involved.
NO₂ is a reddish-brown gas that is acidic in nature.
The brown color arises from dimerization of NO₂ at lower temperatures, and its acidic property comes from reaction with water.
Final Answer: Brown and acidic; Option C is correct.
Confusing NO₂ with other nitrogen oxides (e.g., NO, N₂O).
😢 Uh oh! Incorrect answer, Try again
Recall the properties of nitrogen oxides.
No formula involved.
NO₂ is a reddish-brown gas that is acidic in nature.
The brown color arises from dimerization of NO₂ at lower temperatures, and its acidic property comes from reaction with water.
Final Answer: Brown and acidic; Option C is correct.
Confusing NO₂ with other nitrogen oxides (e.g., NO, N₂O).
The correct decreasing order of boiling point of hydrogen halides is:
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No formula involved.
Analyze boiling points based on intermolecular forces (hydrogen bonding, van der Waals forces).
HF has the highest boiling point due to strong hydrogen bonding, followed by halides with increasing molar masses.
Final Answer: HF > HI > HBr > HCl; Option C is correct.
Overlooking the significant impact of hydrogen bonding in HF.
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Focus on the role of hydrogen bonding and molecular mass in boiling points.
No formula involved.
Analyze boiling points based on intermolecular forces (hydrogen bonding, van der Waals forces).
HF has the highest boiling point due to strong hydrogen bonding, followed by halides with increasing molar masses.
Final Answer: HF > HI > HBr > HCl; Option C is correct.
Overlooking the significant impact of hydrogen bonding in HF.
Identify the incorrect statement from the following:
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No formula involved.
Ozone absorbs ultraviolet (UV) radiation, not infrared (IR) radiation.
IR absorption is more characteristic of greenhouse gases like CO₂.
Final Answer: Option D is incorrect because ozone does not absorb IR radiation.
Assuming ozone absorbs IR radiation like greenhouse gases.
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Differentiate between ozone's UV protection and greenhouse effects.
No formula involved.
Ozone absorbs ultraviolet (UV) radiation, not infrared (IR) radiation.
IR absorption is more characteristic of greenhouse gases like CO₂.
Final Answer: Option D is incorrect because ozone does not absorb IR radiation.
Assuming ozone absorbs IR radiation like greenhouse gases.
First chlorinated organic insecticide prepared is...
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DDT = Dichlorodiphenyltrichloroethane.
DDT (Dichlorodiphenyltrichloroethane) was the first chlorinated organic insecticide prepared.
Recognize historical usage of DDT as an insecticide.
Final answer: DDT.
Confusing DDT with other chlorinated compounds.
😢 Uh oh! Incorrect answer, Try again
Recall DDT synthesis and significance.
DDT = Dichlorodiphenyltrichloroethane.
DDT (Dichlorodiphenyltrichloroethane) was the first chlorinated organic insecticide prepared.
Recognize historical usage of DDT as an insecticide.
Final answer: DDT.
Confusing DDT with other chlorinated compounds.
Sequence of reactions yielding Br-substituted products is...
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Addition-elimination pathways for Br substitution.
Recognize reaction steps: addition, substitution, and elimination pathways involving Br₂ and NaNH₂.
Follow sequential mechanism: CH₂=CH₂ → Br-substituted products.
Final products involve multiple bromination and alkane formation.
Misunderstanding intermediate steps in bromination sequence.
😢 Uh oh! Incorrect answer, Try again
Carefully track intermediates and reagents.
Addition-elimination pathways for Br substitution.
Recognize reaction steps: addition, substitution, and elimination pathways involving Br₂ and NaNH₂.
Follow sequential mechanism: CH₂=CH₂ → Br-substituted products.
Final products involve multiple bromination and alkane formation.
Misunderstanding intermediate steps in bromination sequence.
Percentage of carbon in an organic compound combusting to CO₂ is...
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%C = (mass of C in CO₂ / mass of compound) × 100.
Calculate %C using the relation: (mass of C in CO₂ / mass of compound) × 100.
Use data: (12/44) × (0.22/0.48) × 100 = 12.5%.
Carbon percentage = 12.5%.
Miscalculating %C using incorrect ratios.
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Carefully compute based on given mass ratios.
%C = (mass of C in CO₂ / mass of compound) × 100.
Calculate %C using the relation: (mass of C in CO₂ / mass of compound) × 100.
Use data: (12/44) × (0.22/0.48) × 100 = 12.5%.
Carbon percentage = 12.5%.
Miscalculating %C using incorrect ratios.
Nitrate decomposing to NO₂ on heating is...
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LiNO₃ decomposition: 4LiNO₃ → 2Li₂O + 4NO₂ + O₂.
LiNO₃ decomposes to NO₂ due to its unique thermal decomposition properties.
Recognize that LiNO₃ decomposition differs from other nitrates.
Final product: 4LiNO₃ → 2Li₂O + 4NO₂ + O₂.
Confusing LiNO₃ decomposition with other alkali nitrates.
😢 Uh oh! Incorrect answer, Try again
Focus on differences in thermal decomposition of nitrates.
LiNO₃ decomposition: 4LiNO₃ → 2Li₂O + 4NO₂ + O₂.
LiNO₃ decomposes to NO₂ due to its unique thermal decomposition properties.
Recognize that LiNO₃ decomposition differs from other nitrates.
Final product: 4LiNO₃ → 2Li₂O + 4NO₂ + O₂.
Confusing LiNO₃ decomposition with other alkali nitrates.
Property not applicable to ionic hydrides is...
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Ionic hydrides: Non-volatile, crystalline, non-conducting.
Ionic hydrides are generally non-volatile, crystalline, and non-conducting in solid state.
Focus on physical properties of ionic hydrides.
Volatility is not applicable to ionic hydrides.
Mistaking ionic hydrides for covalent hydrides.
😢 Uh oh! Incorrect answer, Try again
Recall high melting points and crystalline nature of ionic hydrides.
Ionic hydrides: Non-volatile, crystalline, non-conducting.
Ionic hydrides are generally non-volatile, crystalline, and non-conducting in solid state.
Focus on physical properties of ionic hydrides.
Volatility is not applicable to ionic hydrides.
Mistaking ionic hydrides for covalent hydrides.
2-Methylpropane can be prepared by the Wurtz reaction. The haloalkanes taken are...
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RCl + Na → Hydrocarbon (alkane) formation.
Wurtz reaction involves metallic sodium in dry ether reacting with haloalkanes to produce alkanes.
Identify 2-methylpropane as the desired product formed from chloromethane and 2-chloropropane.
Final product is 2-methylpropane.
Misinterpreting haloalkane pairing for Wurtz reaction.
😢 Uh oh! Incorrect answer, Try again
Recall Wurtz reaction and pairing mechanism.
RCl + Na → Hydrocarbon (alkane) formation.
Wurtz reaction involves metallic sodium in dry ether reacting with haloalkanes to produce alkanes.
Identify 2-methylpropane as the desired product formed from chloromethane and 2-chloropropane.
Final product is 2-methylpropane.
Misinterpreting haloalkane pairing for Wurtz reaction.
Reaction between moist SO₂ and acidified permanganate...
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Oxidation: SO₂ → SO₄²⁻; Reduction: MnO₄⁻ → Mn²⁺.
Reaction involves oxidation of SO₂ to SO₄²⁻ and reduction of MnO₄⁻ to Mn²⁺ in acidic medium.
Balance the reaction in acidic medium: MnO₄⁻ + SO₂ → Mn²⁺ + SO₄²⁻.
Final result: SO₂ → SO₄²⁻; MnO₄⁻ → Mn²⁺.
Misidentifying oxidized and reduced species in redox reaction.
😢 Uh oh! Incorrect answer, Try again
Focus on oxidation states and redox balancing.
Oxidation: SO₂ → SO₄²⁻; Reduction: MnO₄⁻ → Mn²⁺.
Reaction involves oxidation of SO₂ to SO₄²⁻ and reduction of MnO₄⁻ to Mn²⁺ in acidic medium.
Balance the reaction in acidic medium: MnO₄⁻ + SO₂ → Mn²⁺ + SO₄²⁻.
Final result: SO₂ → SO₄²⁻; MnO₄⁻ → Mn²⁺.
Misidentifying oxidized and reduced species in redox reaction.
Sodium ethanoate on heating with soda lime gives ‘X’. Electrolysis gives ‘Y’. Identify ‘X’ and ‘Y’.
🥳 Wohoo! Correct answer
X = Decarboxylation; Y = Kolbe’s electrolysis
Decarboxylation: Sodium ethanoate + NaOH → Methane (X). Kolbe’s electrolysis: 2CH₃COONa → Ethane (Y).
Decarboxylation: CO₂ released; Electrolysis: Dimerization of CH₃ radicals.
Final result: X = Methane, Y = Ethane.
Misinterpreting electrolysis products or decarboxylation intermediates.
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Differentiate between reactions for decarboxylation and electrolysis.
X = Decarboxylation; Y = Kolbe’s electrolysis
Decarboxylation: Sodium ethanoate + NaOH → Methane (X). Kolbe’s electrolysis: 2CH₃COONa → Ethane (Y).
Decarboxylation: CO₂ released; Electrolysis: Dimerization of CH₃ radicals.
Final result: X = Methane, Y = Ethane.
Misinterpreting electrolysis products or decarboxylation intermediates.